Integrand size = 50, antiderivative size = 448 \[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=-\frac {2 (a-b) \sqrt {a+b} \left (35 a b B-12 a^2 C+9 b^2 C\right ) \cot (c+d x) E\left (\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (1+\sec (c+d x))}{a-b}}}{15 d}-\frac {2 \sqrt {a+b} \left (a b^2 (35 B-12 C)-b^3 (5 B-9 C)+30 a^3 C-3 a^2 b (15 B+4 C)\right ) \cot (c+d x) \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (1+\sec (c+d x))}{a-b}}}{15 d}-\frac {2 a^2 \sqrt {a+b} (b B-a C) \cot (c+d x) \operatorname {EllipticPi}\left (\frac {a+b}{a},\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (1+\sec (c+d x))}{a-b}}}{d}+\frac {2 b^2 (5 b B+3 a C) \sqrt {a+b \sec (c+d x)} \tan (c+d x)}{15 d}+\frac {2 b^2 C (a+b \sec (c+d x))^{3/2} \tan (c+d x)}{5 d} \]
-2/15*(a-b)*(35*B*a*b-12*C*a^2+9*C*b^2)*cot(d*x+c)*EllipticE((a+b*sec(d*x+ c))^(1/2)/(a+b)^(1/2),((a+b)/(a-b))^(1/2))*(a+b)^(1/2)*(b*(1-sec(d*x+c))/( a+b))^(1/2)*(-b*(1+sec(d*x+c))/(a-b))^(1/2)/d-2/15*(a*b^2*(35*B-12*C)-b^3* (5*B-9*C)+30*a^3*C-3*a^2*b*(15*B+4*C))*cot(d*x+c)*EllipticF((a+b*sec(d*x+c ))^(1/2)/(a+b)^(1/2),((a+b)/(a-b))^(1/2))*(a+b)^(1/2)*(b*(1-sec(d*x+c))/(a +b))^(1/2)*(-b*(1+sec(d*x+c))/(a-b))^(1/2)/d-2*a^2*(B*b-C*a)*cot(d*x+c)*El lipticPi((a+b*sec(d*x+c))^(1/2)/(a+b)^(1/2),(a+b)/a,((a+b)/(a-b))^(1/2))*( a+b)^(1/2)*(b*(1-sec(d*x+c))/(a+b))^(1/2)*(-b*(1+sec(d*x+c))/(a-b))^(1/2)/ d+2/5*b^2*C*(a+b*sec(d*x+c))^(3/2)*tan(d*x+c)/d+2/15*b^2*(5*B*b+3*C*a)*(a+ b*sec(d*x+c))^(1/2)*tan(d*x+c)/d
Time = 25.76 (sec) , antiderivative size = 689, normalized size of antiderivative = 1.54 \[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=\frac {2 \sqrt {\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )} \sqrt {\cos ^2\left (\frac {1}{2} (c+d x)\right ) \sec (c+d x)} (a+b \sec (c+d x))^{5/2} (b B-a C+b C \sec (c+d x)) \left (-b (a+b) \left (35 a b B-12 a^2 C+9 b^2 C\right ) E\left (\arcsin \left (\tan \left (\frac {1}{2} (c+d x)\right )\right )|\frac {a-b}{a+b}\right ) \sec ^2\left (\frac {1}{2} (c+d x)\right ) \sqrt {\frac {(b+a \cos (c+d x)) \sec ^2\left (\frac {1}{2} (c+d x)\right )}{a+b}}+b (a+b) \left (-15 a^2 C+3 a b (10 B+C)+b^2 (5 B+9 C)\right ) \operatorname {EllipticF}\left (\arcsin \left (\tan \left (\frac {1}{2} (c+d x)\right )\right ),\frac {a-b}{a+b}\right ) \sec ^2\left (\frac {1}{2} (c+d x)\right ) \sqrt {\frac {(b+a \cos (c+d x)) \sec ^2\left (\frac {1}{2} (c+d x)\right )}{a+b}}-15 a^2 (b B-a C) \left ((a-b) \operatorname {EllipticF}\left (\arcsin \left (\tan \left (\frac {1}{2} (c+d x)\right )\right ),\frac {a-b}{a+b}\right )-2 a \operatorname {EllipticPi}\left (-1,\arcsin \left (\tan \left (\frac {1}{2} (c+d x)\right )\right ),\frac {a-b}{a+b}\right )\right ) \sec ^2\left (\frac {1}{2} (c+d x)\right ) \sqrt {\frac {(b+a \cos (c+d x)) \sec ^2\left (\frac {1}{2} (c+d x)\right )}{a+b}}-b \left (35 a b B-12 a^2 C+9 b^2 C\right ) (b+a \cos (c+d x)) \left (\cos (c+d x) \sec ^2\left (\frac {1}{2} (c+d x)\right )\right )^{3/2} \sec (c+d x) \tan \left (\frac {1}{2} (c+d x)\right )\right )}{15 d (b+a \cos (c+d x))^3 (b C+b B \cos (c+d x)-a C \cos (c+d x)) \sec ^2\left (\frac {1}{2} (c+d x)\right )^{3/2} \sec ^{\frac {7}{2}}(c+d x)}+\frac {\cos ^3(c+d x) (a+b \sec (c+d x))^{5/2} (b B-a C+b C \sec (c+d x)) \left (\frac {2}{15} b \left (35 a b B-12 a^2 C+9 b^2 C\right ) \sin (c+d x)+\frac {2}{15} \sec (c+d x) \left (5 b^3 B \sin (c+d x)+6 a b^2 C \sin (c+d x)\right )+\frac {2}{5} b^3 C \sec (c+d x) \tan (c+d x)\right )}{d (b+a \cos (c+d x))^2 (b C+b B \cos (c+d x)-a C \cos (c+d x))} \]
Integrate[(a + b*Sec[c + d*x])^(3/2)*(a*b*B - a^2*C + b^2*B*Sec[c + d*x] + b^2*C*Sec[c + d*x]^2),x]
(2*Sqrt[Cos[c + d*x]*Sec[(c + d*x)/2]^2]*Sqrt[Cos[(c + d*x)/2]^2*Sec[c + d *x]]*(a + b*Sec[c + d*x])^(5/2)*(b*B - a*C + b*C*Sec[c + d*x])*(-(b*(a + b )*(35*a*b*B - 12*a^2*C + 9*b^2*C)*EllipticE[ArcSin[Tan[(c + d*x)/2]], (a - b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2 ]^2)/(a + b)]) + b*(a + b)*(-15*a^2*C + 3*a*b*(10*B + C) + b^2*(5*B + 9*C) )*EllipticF[ArcSin[Tan[(c + d*x)/2]], (a - b)/(a + b)]*Sec[(c + d*x)/2]^2* Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] - 15*a^2*(b*B - a* C)*((a - b)*EllipticF[ArcSin[Tan[(c + d*x)/2]], (a - b)/(a + b)] - 2*a*Ell ipticPi[-1, ArcSin[Tan[(c + d*x)/2]], (a - b)/(a + b)])*Sec[(c + d*x)/2]^2 *Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] - b*(35*a*b*B - 1 2*a^2*C + 9*b^2*C)*(b + a*Cos[c + d*x])*(Cos[c + d*x]*Sec[(c + d*x)/2]^2)^ (3/2)*Sec[c + d*x]*Tan[(c + d*x)/2]))/(15*d*(b + a*Cos[c + d*x])^3*(b*C + b*B*Cos[c + d*x] - a*C*Cos[c + d*x])*(Sec[(c + d*x)/2]^2)^(3/2)*Sec[c + d* x]^(7/2)) + (Cos[c + d*x]^3*(a + b*Sec[c + d*x])^(5/2)*(b*B - a*C + b*C*Se c[c + d*x])*((2*b*(35*a*b*B - 12*a^2*C + 9*b^2*C)*Sin[c + d*x])/15 + (2*Se c[c + d*x]*(5*b^3*B*Sin[c + d*x] + 6*a*b^2*C*Sin[c + d*x]))/15 + (2*b^3*C* Sec[c + d*x]*Tan[c + d*x])/5))/(d*(b + a*Cos[c + d*x])^2*(b*C + b*B*Cos[c + d*x] - a*C*Cos[c + d*x]))
Time = 1.94 (sec) , antiderivative size = 467, normalized size of antiderivative = 1.04, number of steps used = 16, number of rules used = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {3042, 4529, 3042, 4406, 27, 3042, 4544, 27, 3042, 4546, 3042, 4409, 3042, 4271, 4319, 4492}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int (a+b \sec (c+d x))^{3/2} \left (a^2 (-C)+a b B+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )^{3/2} \left (a^2 (-C)+a b B+b^2 B \csc \left (c+d x+\frac {\pi }{2}\right )+b^2 C \csc \left (c+d x+\frac {\pi }{2}\right )^2\right )dx\) |
| \(\Big \downarrow \) 4529 |
| \(\displaystyle \frac {\int (a+b \sec (c+d x))^{5/2} \left (C \sec (c+d x) b^3+(b B-a C) b^2\right )dx}{b^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \left (a+b \csc \left (c+d x+\frac {\pi }{2}\right )\right )^{5/2} \left (C \csc \left (c+d x+\frac {\pi }{2}\right ) b^3+(b B-a C) b^2\right )dx}{b^2}\) |
| \(\Big \downarrow \) 4406 |
| \(\displaystyle \frac {\frac {2}{5} \int \frac {1}{2} \sqrt {a+b \sec (c+d x)} \left ((5 b B+3 a C) \sec ^2(c+d x) b^4+\left (-5 C a^2+10 b B a+3 b^2 C\right ) \sec (c+d x) b^3+5 a^2 (b B-a C) b^2\right )dx+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {1}{5} \int \sqrt {a+b \sec (c+d x)} \left ((5 b B+3 a C) \sec ^2(c+d x) b^4+\left (-5 C a^2+10 b B a+3 b^2 C\right ) \sec (c+d x) b^3+5 a^2 (b B-a C) b^2\right )dx+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{5} \int \sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )} \left ((5 b B+3 a C) \csc \left (c+d x+\frac {\pi }{2}\right )^2 b^4+\left (-5 C a^2+10 b B a+3 b^2 C\right ) \csc \left (c+d x+\frac {\pi }{2}\right ) b^3+5 a^2 (b B-a C) b^2\right )dx+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4544 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {2}{3} \int \frac {\left (-12 C a^2+35 b B a+9 b^2 C\right ) \sec ^2(c+d x) b^4+\left (-30 C a^3+45 b B a^2+12 b^2 C a+5 b^3 B\right ) \sec (c+d x) b^3+15 a^3 (b B-a C) b^2}{2 \sqrt {a+b \sec (c+d x)}}dx+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \int \frac {\left (-12 C a^2+35 b B a+9 b^2 C\right ) \sec ^2(c+d x) b^4+\left (-30 C a^3+45 b B a^2+12 b^2 C a+5 b^3 B\right ) \sec (c+d x) b^3+15 a^3 (b B-a C) b^2}{\sqrt {a+b \sec (c+d x)}}dx+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \int \frac {\left (-12 C a^2+35 b B a+9 b^2 C\right ) \csc \left (c+d x+\frac {\pi }{2}\right )^2 b^4+\left (-30 C a^3+45 b B a^2+12 b^2 C a+5 b^3 B\right ) \csc \left (c+d x+\frac {\pi }{2}\right ) b^3+15 a^3 (b B-a C) b^2}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4546 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\sec (c+d x) (\sec (c+d x)+1)}{\sqrt {a+b \sec (c+d x)}}dx+\int \frac {15 b^2 (b B-a C) a^3+\left (b^3 \left (-30 C a^3+45 b B a^2+12 b^2 C a+5 b^3 B\right )-b^4 \left (-12 C a^2+35 b B a+9 b^2 C\right )\right ) \sec (c+d x)}{\sqrt {a+b \sec (c+d x)}}dx\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right )+1\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx+\int \frac {15 b^2 (b B-a C) a^3+\left (b^3 \left (-30 C a^3+45 b B a^2+12 b^2 C a+5 b^3 B\right )-b^4 \left (-12 C a^2+35 b B a+9 b^2 C\right )\right ) \csc \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4409 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (15 a^3 b^2 (b B-a C) \int \frac {1}{\sqrt {a+b \sec (c+d x)}}dx+b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right )+1\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx-b^3 \left (30 a^3 C-3 a^2 b (15 B+4 C)+a b^2 (35 B-12 C)-b^3 (5 B-9 C)\right ) \int \frac {\sec (c+d x)}{\sqrt {a+b \sec (c+d x)}}dx\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (15 a^3 b^2 (b B-a C) \int \frac {1}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx+b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right )+1\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx-b^3 \left (30 a^3 C-3 a^2 b (15 B+4 C)+a b^2 (35 B-12 C)-b^3 (5 B-9 C)\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4271 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right )+1\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx-b^3 \left (30 a^3 C-3 a^2 b (15 B+4 C)+a b^2 (35 B-12 C)-b^3 (5 B-9 C)\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx-\frac {30 a^2 b^2 \sqrt {a+b} (b B-a C) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} \operatorname {EllipticPi}\left (\frac {a+b}{a},\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right )}{d}\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4319 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (b^4 \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \int \frac {\csc \left (c+d x+\frac {\pi }{2}\right ) \left (\csc \left (c+d x+\frac {\pi }{2}\right )+1\right )}{\sqrt {a+b \csc \left (c+d x+\frac {\pi }{2}\right )}}dx-\frac {30 a^2 b^2 \sqrt {a+b} (b B-a C) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} \operatorname {EllipticPi}\left (\frac {a+b}{a},\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right )}{d}-\frac {2 b^2 \sqrt {a+b} \left (30 a^3 C-3 a^2 b (15 B+4 C)+a b^2 (35 B-12 C)-b^3 (5 B-9 C)\right ) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right )}{d}\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
| \(\Big \downarrow \) 4492 |
| \(\displaystyle \frac {\frac {1}{5} \left (\frac {1}{3} \left (-\frac {2 b^2 (a-b) \sqrt {a+b} \left (-12 a^2 C+35 a b B+9 b^2 C\right ) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} E\left (\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right )}{d}-\frac {30 a^2 b^2 \sqrt {a+b} (b B-a C) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} \operatorname {EllipticPi}\left (\frac {a+b}{a},\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right )}{d}-\frac {2 b^2 \sqrt {a+b} \left (30 a^3 C-3 a^2 b (15 B+4 C)+a b^2 (35 B-12 C)-b^3 (5 B-9 C)\right ) \cot (c+d x) \sqrt {\frac {b (1-\sec (c+d x))}{a+b}} \sqrt {-\frac {b (\sec (c+d x)+1)}{a-b}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {a+b \sec (c+d x)}}{\sqrt {a+b}}\right ),\frac {a+b}{a-b}\right )}{d}\right )+\frac {2 b^4 (3 a C+5 b B) \tan (c+d x) \sqrt {a+b \sec (c+d x)}}{3 d}\right )+\frac {2 b^4 C \tan (c+d x) (a+b \sec (c+d x))^{3/2}}{5 d}}{b^2}\) |
Int[(a + b*Sec[c + d*x])^(3/2)*(a*b*B - a^2*C + b^2*B*Sec[c + d*x] + b^2*C *Sec[c + d*x]^2),x]
((2*b^4*C*(a + b*Sec[c + d*x])^(3/2)*Tan[c + d*x])/(5*d) + (((-2*(a - b)*b ^2*Sqrt[a + b]*(35*a*b*B - 12*a^2*C + 9*b^2*C)*Cot[c + d*x]*EllipticE[ArcS in[Sqrt[a + b*Sec[c + d*x]]/Sqrt[a + b]], (a + b)/(a - b)]*Sqrt[(b*(1 - Se c[c + d*x]))/(a + b)]*Sqrt[-((b*(1 + Sec[c + d*x]))/(a - b))])/d - (2*b^2* Sqrt[a + b]*(a*b^2*(35*B - 12*C) - b^3*(5*B - 9*C) + 30*a^3*C - 3*a^2*b*(1 5*B + 4*C))*Cot[c + d*x]*EllipticF[ArcSin[Sqrt[a + b*Sec[c + d*x]]/Sqrt[a + b]], (a + b)/(a - b)]*Sqrt[(b*(1 - Sec[c + d*x]))/(a + b)]*Sqrt[-((b*(1 + Sec[c + d*x]))/(a - b))])/d - (30*a^2*b^2*Sqrt[a + b]*(b*B - a*C)*Cot[c + d*x]*EllipticPi[(a + b)/a, ArcSin[Sqrt[a + b*Sec[c + d*x]]/Sqrt[a + b]], (a + b)/(a - b)]*Sqrt[(b*(1 - Sec[c + d*x]))/(a + b)]*Sqrt[-((b*(1 + Sec[ c + d*x]))/(a - b))])/d)/3 + (2*b^4*(5*b*B + 3*a*C)*Sqrt[a + b*Sec[c + d*x ]]*Tan[c + d*x])/(3*d))/5)/b^2
3.10.75.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[1/Sqrt[csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_)], x_Symbol] :> Simp[2*(Rt[a + b, 2]/(a*d*Cot[c + d*x]))*Sqrt[b*((1 - Csc[c + d*x])/(a + b))]*Sqrt[(-b) *((1 + Csc[c + d*x])/(a - b))]*EllipticPi[(a + b)/a, ArcSin[Sqrt[a + b*Csc[ c + d*x]]/Rt[a + b, 2]], (a + b)/(a - b)], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0]
Int[csc[(e_.) + (f_.)*(x_)]/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_S ymbol] :> Simp[-2*(Rt[a + b, 2]/(b*f*Cot[e + f*x]))*Sqrt[(b*(1 - Csc[e + f* x]))/(a + b)]*Sqrt[(-b)*((1 + Csc[e + f*x])/(a - b))]*EllipticF[ArcSin[Sqrt [a + b*Csc[e + f*x]]/Rt[a + b, 2]], (a + b)/(a - b)], x] /; FreeQ[{a, b, e, f}, x] && NeQ[a^2 - b^2, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_)*(csc[(e_.) + (f_.)*(x_)]*(d _.) + (c_)), x_Symbol] :> Simp[(-b)*d*Cot[e + f*x]*((a + b*Csc[e + f*x])^(m - 1)/(f*m)), x] + Simp[1/m Int[(a + b*Csc[e + f*x])^(m - 2)*Simp[a^2*c*m + (b^2*d*(m - 1) + 2*a*b*c*m + a^2*d*m)*Csc[e + f*x] + b*(b*c*m + a*d*(2*m - 1))*Csc[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b* c - a*d, 0] && GtQ[m, 1] && NeQ[a^2 - b^2, 0] && IntegerQ[2*m]
Int[(csc[(e_.) + (f_.)*(x_)]*(d_.) + (c_))/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_ .) + (a_)], x_Symbol] :> Simp[c Int[1/Sqrt[a + b*Csc[e + f*x]], x], x] + Simp[d Int[Csc[e + f*x]/Sqrt[a + b*Csc[e + f*x]], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
Int[(csc[(e_.) + (f_.)*(x_)]*(csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_)))/Sqrt[c sc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_Symbol] :> Simp[-2*(A*b - a*B)*Rt[a + b*(B/A), 2]*Sqrt[b*((1 - Csc[e + f*x])/(a + b))]*(Sqrt[(-b)*((1 + Csc[e + f*x])/(a - b))]/(b^2*f*Cot[e + f*x]))*EllipticE[ArcSin[Sqrt[a + b*Csc[e + f*x]]/Rt[a + b*(B/A), 2]], (a*A + b*B)/(a*A - b*B)], x] /; FreeQ[{a, b, e, f, A, B}, x] && NeQ[a^2 - b^2, 0] && EqQ[A^2 - B^2, 0]
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.), x_Symbol] :> Simp[1/b^2 Int[(a + b*Csc[e + f*x])^(m + 1)*Simp[b*B - a*C + b*C*Csc[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && EqQ[A*b^2 - a*b*B + a^2*C, 0]
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_.), x_Symbol] :> Simp[(-C)*Cot [e + f*x]*((a + b*Csc[e + f*x])^m/(f*(m + 1))), x] + Simp[1/(m + 1) Int[( a + b*Csc[e + f*x])^(m - 1)*Simp[a*A*(m + 1) + ((A*b + a*B)*(m + 1) + b*C*m )*Csc[e + f*x] + (b*B*(m + 1) + a*C*m)*Csc[e + f*x]^2, x], x], x] /; FreeQ[ {a, b, e, f, A, B, C}, x] && NeQ[a^2 - b^2, 0] && IGtQ[2*m, 0]
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_. ))/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_Symbol] :> Int[(A + (B - C )*Csc[e + f*x])/Sqrt[a + b*Csc[e + f*x]], x] + Simp[C Int[Csc[e + f*x]*(( 1 + Csc[e + f*x])/Sqrt[a + b*Csc[e + f*x]]), x], x] /; FreeQ[{a, b, e, f, A , B, C}, x] && NeQ[a^2 - b^2, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(4745\) vs. \(2(409)=818\).
Time = 24.27 (sec) , antiderivative size = 4746, normalized size of antiderivative = 10.59
| method | result | size |
| default | \(\text {Expression too large to display}\) | \(4746\) |
| parts | \(\text {Expression too large to display}\) | \(4969\) |
int((a+b*sec(d*x+c))^(3/2)*(B*a*b-C*a^2+b^2*B*sec(d*x+c)+b^2*C*sec(d*x+c)^ 2),x,method=_RETURNVERBOSE)
2/15/d*(a+b*sec(d*x+c))^(1/2)/(b+a*cos(d*x+c))/(1+cos(d*x+c))*(9*C*a*b^3*c os(d*x+c)*sin(d*x+c)+35*B*a^2*b^2*cos(d*x+c)*sin(d*x+c)+5*B*a*b^3*cos(d*x+ c)*sin(d*x+c)-12*C*a^3*b*cos(d*x+c)*sin(d*x+c)+6*C*a^2*b^2*cos(d*x+c)*sin( d*x+c)-5*B*EllipticF(cot(d*x+c)-csc(d*x+c),((a-b)/(a+b))^(1/2))*(cos(d*x+c )/(1+cos(d*x+c)))^(1/2)*(1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*b^ 4-9*C*EllipticF(cot(d*x+c)-csc(d*x+c),((a-b)/(a+b))^(1/2))*(cos(d*x+c)/(1+ cos(d*x+c)))^(1/2)*(1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*b^4+3*C *b^4*tan(d*x+c)*sec(d*x+c)+40*B*a*b^3*sin(d*x+c)-6*C*a^2*b^2*sin(d*x+c)+9* C*a*b^3*sin(d*x+c)+9*b^3*C*a*tan(d*x+c)-30*B*EllipticPi(cot(d*x+c)-csc(d*x +c),-1,((a-b)/(a+b))^(1/2))*(cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*(1/(a+b)*(b+ a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*a^3*b*cos(d*x+c)^2+15*B*EllipticF(cot( d*x+c)-csc(d*x+c),((a-b)/(a+b))^(1/2))*(cos(d*x+c)/(1+cos(d*x+c)))^(1/2)*( 1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*a^3*b*cos(d*x+c)^2-60*B*Ell ipticPi(cot(d*x+c)-csc(d*x+c),-1,((a-b)/(a+b))^(1/2))*(cos(d*x+c)/(1+cos(d *x+c)))^(1/2)*(1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*a^3*b*cos(d* x+c)+30*B*EllipticF(cot(d*x+c)-csc(d*x+c),((a-b)/(a+b))^(1/2))*(cos(d*x+c) /(1+cos(d*x+c)))^(1/2)*(1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*a^3 *b*cos(d*x+c)+9*C*(1/(a+b)*(b+a*cos(d*x+c))/(1+cos(d*x+c)))^(1/2)*Elliptic E(cot(d*x+c)-csc(d*x+c),((a-b)/(a+b))^(1/2))*(cos(d*x+c)/(1+cos(d*x+c)))^( 1/2)*b^4+9*C*b^4*sin(d*x+c)-90*B*EllipticF(cot(d*x+c)-csc(d*x+c),((a-b)...
\[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=\int { {\left (C b^{2} \sec \left (d x + c\right )^{2} + B b^{2} \sec \left (d x + c\right ) - C a^{2} + B a b\right )} {\left (b \sec \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \,d x } \]
integrate((a+b*sec(d*x+c))^(3/2)*(B*a*b-C*a^2+b^2*B*sec(d*x+c)+b^2*C*sec(d *x+c)^2),x, algorithm="fricas")
integral((C*b^3*sec(d*x + c)^3 - C*a^3 + B*a^2*b + (C*a*b^2 + B*b^3)*sec(d *x + c)^2 - (C*a^2*b - 2*B*a*b^2)*sec(d*x + c))*sqrt(b*sec(d*x + c) + a), x)
\[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=- \int C a^{3} \sqrt {a + b \sec {\left (c + d x \right )}}\, dx - \int \left (- B a^{2} b \sqrt {a + b \sec {\left (c + d x \right )}}\right )\, dx - \int \left (- B b^{3} \sqrt {a + b \sec {\left (c + d x \right )}} \sec ^{2}{\left (c + d x \right )}\right )\, dx - \int \left (- C b^{3} \sqrt {a + b \sec {\left (c + d x \right )}} \sec ^{3}{\left (c + d x \right )}\right )\, dx - \int \left (- 2 B a b^{2} \sqrt {a + b \sec {\left (c + d x \right )}} \sec {\left (c + d x \right )}\right )\, dx - \int \left (- C a b^{2} \sqrt {a + b \sec {\left (c + d x \right )}} \sec ^{2}{\left (c + d x \right )}\right )\, dx - \int C a^{2} b \sqrt {a + b \sec {\left (c + d x \right )}} \sec {\left (c + d x \right )}\, dx \]
-Integral(C*a**3*sqrt(a + b*sec(c + d*x)), x) - Integral(-B*a**2*b*sqrt(a + b*sec(c + d*x)), x) - Integral(-B*b**3*sqrt(a + b*sec(c + d*x))*sec(c + d*x)**2, x) - Integral(-C*b**3*sqrt(a + b*sec(c + d*x))*sec(c + d*x)**3, x ) - Integral(-2*B*a*b**2*sqrt(a + b*sec(c + d*x))*sec(c + d*x), x) - Integ ral(-C*a*b**2*sqrt(a + b*sec(c + d*x))*sec(c + d*x)**2, x) - Integral(C*a* *2*b*sqrt(a + b*sec(c + d*x))*sec(c + d*x), x)
\[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=\int { {\left (C b^{2} \sec \left (d x + c\right )^{2} + B b^{2} \sec \left (d x + c\right ) - C a^{2} + B a b\right )} {\left (b \sec \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \,d x } \]
integrate((a+b*sec(d*x+c))^(3/2)*(B*a*b-C*a^2+b^2*B*sec(d*x+c)+b^2*C*sec(d *x+c)^2),x, algorithm="maxima")
integrate((C*b^2*sec(d*x + c)^2 + B*b^2*sec(d*x + c) - C*a^2 + B*a*b)*(b*s ec(d*x + c) + a)^(3/2), x)
\[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=\int { {\left (C b^{2} \sec \left (d x + c\right )^{2} + B b^{2} \sec \left (d x + c\right ) - C a^{2} + B a b\right )} {\left (b \sec \left (d x + c\right ) + a\right )}^{\frac {3}{2}} \,d x } \]
integrate((a+b*sec(d*x+c))^(3/2)*(B*a*b-C*a^2+b^2*B*sec(d*x+c)+b^2*C*sec(d *x+c)^2),x, algorithm="giac")
integrate((C*b^2*sec(d*x + c)^2 + B*b^2*sec(d*x + c) - C*a^2 + B*a*b)*(b*s ec(d*x + c) + a)^(3/2), x)
Timed out. \[ \int (a+b \sec (c+d x))^{3/2} \left (a b B-a^2 C+b^2 B \sec (c+d x)+b^2 C \sec ^2(c+d x)\right ) \, dx=\int {\left (a+\frac {b}{\cos \left (c+d\,x\right )}\right )}^{3/2}\,\left (\frac {B\,b^2}{\cos \left (c+d\,x\right )}-C\,a^2+\frac {C\,b^2}{{\cos \left (c+d\,x\right )}^2}+B\,a\,b\right ) \,d x \]
int((a + b/cos(c + d*x))^(3/2)*((B*b^2)/cos(c + d*x) - C*a^2 + (C*b^2)/cos (c + d*x)^2 + B*a*b),x)